yes, `fmt.print()` and its variants (`fmt.println`, `fmt.printf`) write directly to `os.stdout` by default — no manual handling of `os.stdout.write` is required.
In Go, the fmt package provides high-level, convenient I/O functions that abstract away low-level details. Specifically, fmt.Print(), fmt.Println(), and fmt.Printf() all write formatted output to standard output (os.Stdout) unless explicitly redirected.
For example:
package main
import "fmt"
func main() {
fmt.Print("Hello, ") // writes to stdout
fmt.Println("World!") // writes to stdout + newline
fmt.Printf("Value: %d\n", 42) // formatted output to stdout
}This is equivalent — under the hood — to writing to os.Stdout, but you don’t need to manage the io.Writer interface manually. In fact, fmt functions use os.Stdout as their default io.Writer. You can verify this behavior by checking the official documentation, which states:
"Print formats using the default formats for its operands and writes to standard output."
⚠️ Note: If you need to redirect output (e.g., to a file or buffer), you can use fmt.Fprint* variants (like fmt.Fprintf) with a custom io.Writer:
f, _ := os.Create("output.txt")
defer f.Close()
fmt.Fprintf(f, "This goes to a file, not stdout.\n")In summary: use fmt.Print* for simple, stdout-bound output; reserve os.Stdout.Write only when you need raw byte-level control — which is rare in typical application code.
