给定 n 个节点,任务是打印单链表中所有节点的乘积。程序必须从初始节点开始遍历单向链表的所有节点,直到找不到 null。
示例
Input -: 1 2 3 4 5 Output -: 120
在上面的例子中,从第一个节点开始遍历所有节点,即 1, 2 3, 4, 5, 6,它们的乘积为 1*2*3*4*5*6 = 120

下面使用的方法如下
- 获取一个临时指针,比如节点类型的 temp
- 将此临时指针设置为头指针指向的第一个节点
- 当 temp 不为 NULL 时,将 temp 移动到 temp ->next。
- 设置 Product=product*(temp->data)
算法
Start
Step 1 -> create structure of a node and temp, next and head as pointer to a structure node
struct node
int data
struct node *next, *head, *temp
End
Step 2 -> declare function to insert a node in a list
void insert(int val)
struct node* newnode = (struct node*)malloc(sizeof(struct node))
newnode->data = val
IF head= NULL
set head = newnode
set head->next = NULL
End
Else
Set temp=head
Loop While temp->next!=NULL
Set temp=temp->next
End
Set newnode->next=NULL
Set temp->next=newnode
End
Step 3 -> Declare a function to display list
void display()
IF head=NULL
Print no node
End
Else
Set temp=head
Loop While temp!=NULL
Print temp->data
Set temp=temp->next
End
End
Step 4 -> declare a function to find alternate nodes
void product_nodes()
declare int product=1
Set temp=head
Loop While temp!=NULL
Set product=product * (temp->data)
Set temp=temp->next
End
Print product
Step 5 -> in main()
Create nodes using struct node* head = NULL;
Call function insert(10) to insert a node
Call display() to display the list
Call product_nodes() to find alternate nodes product
Stop示例
#include#include //structure of a node struct node{ int data; struct node *next; }*head,*temp; //function for inserting nodes into a list void insert(int val){ struct node* newnode = (struct node*)malloc(sizeof(struct node)); newnode->data = val; newnode->next = NULL; if(head == NULL){ head = newnode; temp = head; } else { temp->next=newnode; temp=temp->next; } } //function for displaying a list void display(){ if(head==NULL) printf("no node "); else{ temp=head; while(temp!=NULL){ printf("%d ",temp->data); temp=temp->next; } } } //function for finding product void product_nodes(){ int product=1; temp=head; while(temp!=NULL){ product=product * (temp->data); temp=temp->next; } printf(" product of nodes is : %d" ,product); } int main(){ //creating list struct node* head = NULL; //inserting elements into a list insert(1); insert(2); insert(3); insert(4); insert(5); insert(6); //displaying the list printf("linked list is : "); display(); //calling function for finding prodouct Product_nodes(); return 0; }
输出
linked list is : 1 2 3 4 5 6 product of nodes is : 720










