在 Go 中解析从 AWS CodePipeline 发送到 AWS Lambda 的 UserParameters

语境

我尝试在生成的 aws codepipeline 模板中设置 userparameters 配置，

name: ...
actions:
  - name: invoke-lambda
    actiontypeid:
      category: invoke
      owner: aws
      provider: lambda
      version: '1'
    configuration:
      functionname: examplelambdafunction
      userparameters: '{"example":"user-parameters"}'

在用 go 编写的 aws lambda 上对其进行测试时，需要比平时更长的时间才能找到处理程序的函数定义，以解析将发送的 aws codepipeline json 事件，例如：

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{
    "codepipeline.job": {
        "id": "11111111-abcd-1111-abcd-111111abcdef",
        "accountid": "111111111111",
        "data": {
            "actionconfiguration": {
                "configuration": {
                    "functionname": "examplelambdafunction",
                    "userparameters": "{\"example\":\"user-parameters\"}"
                }
            },
            "inputartifacts": [
               ...
            ],
            ...
        }
    }
}

解决方案

使用 github.com/aws/aws-lambda-go/events 包链接，其中包含 events.codepipelinejobevent，可帮助解组正在发送的 aws codepipeline json 事件

package main

import (
    "context"
    "fmt"
    "github.com/aws/aws-lambda-go/events"
    "github.com/aws/aws-lambda-go/lambda"
)

func Handler(ctx context.Context, event events.CodePipelineJobEvent) (string, error) {
    fmt.Printf("received codepipeline event function name: %+v\n", event.CodePipelineJob.Data.ActionConfiguration.Configuration.FunctionName)
    fmt.Printf("received codepipeline event user parameters: %+v\n", event.CodePipelineJob.Data.ActionConfiguration.Configuration.UserParameters)
    return "cool", nil
}

func main() {
    lambda.Start(Handler)
}

参考

• https://docs.aws.amazon.com/codepipeline/latest/userguide/action-reference-lambda.html
• https://docs.aws.amazon.com/codepipeline/latest/userguide/action-reference-lambda.html#action-reference-lambda-event
• https://github.com/aws/aws-lambda-go/blob/main/events/codepipeline_job.go